Mastering Vertical Projectile Motion in Grade 12
A definitive guide to setting reference directions, choosing the right equation of motion, and avoiding the sign errors that cost the most marks.
Reviewed by Mr L Gomane, SACE-registered Mathematics & Physical Sciences educator
Vertical projectile motion remains one of the highest-yield topics in NSC Physical Sciences Paper 1. Despite the equations being straightforward, learners consistently lose marks to sign errors in acceleration rather than to the physics itself.
1. Choose your positive direction early
Before writing down any formula, explicitly define which direction is positive. If upward is positive, gravitational acceleration must always be entered as .
Key rule to remember
At the maximum height of any vertical projectile, instantaneous velocity is always 0 m/s, even though acceleration remains 9,8 m/s² downward.
2. Step-by-step example
A standard exam question: a ball is thrown vertically upwards from the ground at . Calculate the maximum height reached.
Substitute , , and to solve for — no time variable needed.
Which equation of motion requires no time variable?
Show solution
3. Common pitfalls to avoid
- Mixing signed and unsigned values in the same calculation — once you fix a positive direction, every vector quantity must follow it for the rest of the question.
- Forgetting that velocity is zero (not acceleration) at the highest point of the flight.
- Rounding intermediate values instead of carrying full precision through to the final answer.
Want more worked examples like this?
Practise with Grade 12 Physical Sciences past papers